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Five chocolates of different flavours are to be distributed in three different children such that any child get at least 1 chocolate. What is the maximum number of different ways in which this can be distributed?
(A) 120
(B) 130
(C) 140
(D) 150


Answer: (D)

Explanation: Acc. to question
Chocolates can be distributed as [(3, 1, 1)(1, 3, 1)(1, 1, 3)]
or [(2, 2, 1)(2, 1, 2)(1, 2, 2)]
Total number of ways = 3 x 5C3 x 2C1 x 1C1 + 3 x 5C2 x 3C2 x 1C1
= 60 + 90
= 150

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Last Updated : 03 May, 2019
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