Queries for characters in a repeated string

Given a string X. Form a string S by repeating string X multiple times i.e appending string X multiple times with itself. There are Q queries of form i and j. The task is to print “Yes” if the element at index i is same as the element at index j in S else print “No” for each query.

Examples :

Input : X = "geeksforgeeks", Q = 3.
Query 1: 0 8
Query 2: 8 13
Query 3: 6 15

Output :
Yes
Yes
No

String S will be "geeksforgeeksgeeksforgeeks....".
For Query 1, index 0 and index 8 have same element i.e 'g'.
For Query 2, index 8 and index 13 have same element i.e 'g'.
For Query 3, index 6 = 'o' and index 15 = 'e' which are not same.

Let length of string X be n. Observe that element at indexes 0, n, 2n, 3n,…. are same. Similarly for index i, position i, n+i, 2n+i, 3n+i,….. contain same element.
So, for each query, find (i%n) and (j%n) and if both are same for string X.

Below is the implementation of above idea :

C++



filter_none

edit
close

play_arrow

link
brightness_4
code

// Queries for same characters in a repeated
// string
#include<bits/stdc++.h>
using namespace std;
  
// Print whether index i and j have same
// element or not.
void query(char s[], int i, int j)
{
    int n = strlen(s);
  
    // Finding relative position of index i,j.
    i %= n;
    j %= n;
  
    // Checking is element are same at index i, j.
    (s[i]==s[j])? (cout << "Yes" << endl):
                  (cout << "No" << endl);
}
  
// Driven Program
int main()
{
    char X[] = "geeksforgeeks";
  
    query(X, 0, 8);
    query(X, 8, 13);
    query(X, 6, 15);
  
    return 0;
}

chevron_right






                        filter_none









Java














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















// Java Program to Queries for 


// same characters in a  


// repeated string 


import java.io.*; 


  


public class GFG{ 


      


// Print whether index i and j 


// have same element or not 


static void query(String s, int i, 


                  int j) 


{ 


    int n = s.length(); 


  


    // Finding relative position 


    // of index i,j 


    i %= n; 


    j %= n; 


  


    // Checking is element are same 


    // at index i, j 


    if(s.charAt(i) == s.charAt(j)) 


    System.out.println("Yes"); 


    else


    System.out.println("No"); 


} 


  


    // Driver Code 


    static public void main (String[] args) 


    { 


    String X = "geeksforgeeks"; 


  


    query(X, 0, 8); 


    query(X, 8, 13); 


    query(X, 6, 15); 


  


    } 


} 


  


// This code is contributed by vt_m. 



















                        chevron_right







                        filter_none









Python3














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















# Queries for same characters in a repeated 


# string 


  


# Print whether index i and j have same 


# element or not. 


def query(s, i, j): 


    n = len(s) 


  


    # Finding relative position of index i,j. 


    i %= n 


    j %= n 


  


    # Checking is element are same at index i, j. 


    print("Yes") if s[i] == s[j] else print("No") 


  


# Driver code 


if __name__ == "__main__": 


    X = "geeksforgeeks"


    query(X, 0, 8) 


    query(X, 8, 13) 


    query(X, 6, 15) 


  


# This code is contributed by 


# sanjeev2552 



















                        chevron_right







                        filter_none









C#














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















// C# Program to Queries for 


// same characters in a  


// repeated string 


using System; 


  


public class GFG{ 


      


// Print whether index i and j 


// have same element or not 


static void query(string s, int i,  


                  int j) 


{ 


    int n = s.Length; 


  


    // Finding relative position 


    // of index i,j. 


    i %= n; 


    j %= n; 


  


    // Checking is element are  


    // same at index i, j 


    if(s[i] == s[j]) 


    Console.WriteLine("Yes"); 


    else


    Console.WriteLine("No"); 


} 


  


    // Driver Code 


    static public void Main () 


    { 


    string X = "geeksforgeeks"; 


  


    query(X, 0, 8); 


    query(X, 8, 13); 


    query(X, 6, 15); 


  


    } 


} 


  


// This code is contributed by vt_m. 



















                        chevron_right







                        filter_none









PHP














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















<?php 


// Queries for same characters  


// in a repeated string 


  


// Print whether index i and j  


// have same element or not. 


function query($s, $i, $j) 


{ 


    $n = strlen($s); 


  


    // Finding relative position 


    // of index i,j. 


    $i %= $n; 


    $j %= $n; 


  


    // Checking is element are  


    // same at index i, j. 


    if(($s[$i] == $s[$j]))  


        echo "Yes\n" ; 


    else


        echo "No" ; 


} 


  


// Driver Code 


$X = "geeksforgeeks"; 


  


query($X, 0, 8); 


query($X, 8, 13); 


query($X, 6, 15); 


  


// This code is contributed by nitin mittal.  


?> 



















                        chevron_right







                        filter_none










Output :


Yes
Yes
No



This article is contributed by Anuj Chauhan. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.


Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.


Don’t stop now and take your learning to the next level. Learn all the important concepts of Data Structures and Algorithms with the help of the most trusted course: DSA Self Paced. Become industry ready at a student-friendly price.





    

        My Personal Notes
        arrow_drop_up
    

    

        
        

            
            
        

    


Recommended Posts:

Improved By :  vt_m, nitin mittal, sanjeev2552


					
		

    Article Tags : 
Strings

           	
Practice Tags : 
Strings

        

         

         
 
         
        Be the First to upvote.

                

        



        
        
        
        
        

    

            

            1.3
            

            

             
                 Based on 3 vote(s)
                    

            
            
            
            
            
        

        
        

        

        

        

        

        

        


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.