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QA – Placement Quizzes | Trigonometry & Height and Distances | Question 7

Last Updated : 28 Jun, 2021
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From a point A on a level ground, the angle of elevation of the top of a tower is 30 degrees. If the tower is 100 m high, the distance of point A from the foot of the tower is:

(A)

148 m

(B)

156 m

(C)

173 m

(D)

200 m


Answer: (C)

Explanation:

Let QR be the tower. Then, QR = 100 m and angle QAR = 30 degrees. We know, cot 30° = √3 = AQ/QR. Therefore, AQ = 100*√3 = 173 m.


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