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QA – Placement Quizzes | Time Speed Distance | Question 4

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Paul has to travel 24 km. After walking for 1 hour 40 minutes he sees that he has covered 5/7 of the distance left to cover. Find out Paul’s speed in meters per second. (A) 5/3 m/s (B) 7/5 m/s (C) 2/3 m/s (D) 8/5 m/s

Answer: (A)

Explanation: Let the required speed be x km/hr. Distance covered by Paul in 1 hr 40 min = x × 100/60 = 5x/3 km. Remaining distance = (24 – 5x/3) km. Therefore, 5x/3 = 5/7 × (24 – 5x/3) ⇒ 7/5 × 5x/3 = 24 – 5x/3 ⇒ 7x/3 = (72 – 5x)/3 ⇒ 7x = 72 – 5x ⇒ 12x = 72 ⇒ x = 6. Paul’s speed in meters per second = 6 × 5/18 = 5/3 m/s.

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Last Updated : 28 Jun, 2021
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