QA – Placement Quizzes | Time Speed Distance | Question 4

Paul has to travel 24 km. After walking for 1 hour 40 minutes he sees that he has covered 5/7 of the distance left to cover. Find out Paul’s speed in meters per second.
(A) 5/3 m/s
(B) 7/5 m/s
(C) 2/3 m/s
(D) 8/5 m/s


Answer: (A)

Explanation: Let the required speed be x km/hr.
Distance covered by Paul in 1 hr 40 min = x × 100/60 = 5x/3 km.
Remaining distance = (24 – 5x/3) km.
Therefore, 5x/3 = 5/7 × (24 – 5x/3)
⇒ 7/5 × 5x/3 = 24 – 5x/3
⇒ 7x/3 = (72 – 5x)/3
⇒ 7x = 72 – 5x
⇒ 12x = 72 ⇒ x = 6.
Paul’s speed in meters per second = 6 × 5/18 = 5/3 m/s.

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