A policeman sees a thief at a distance of 100 meters and starts to chase him. The thief sees him and starts to run too. If the thief is running at the speed of 8 km/hr and the policeman is running at the speed of 10 km/hr, find out the distance covered by the thief before the policeman catches him.
(A) 250 meters
(B) 400 meters
(C) 450 meters
(D) 401 meters
Explanation: We can safely assume that the policeman is running in the same direction as the thief.
Speed of policeman w.r.t thief = (10 – 8) = 2 km/hr.
Time taken by policeman to cover the 100m distance between him and the thief = (100/1000) / 2 = 1/20 hr.
Therefore, the distance covered by thief in 1/20 hrs = 8 × 1/20 = 2/5 km = 400 meters.
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