Two cars with speed of 15 kmph and 30 kmph respectively are 100 km apart and face each other. The distance between them 5 minutes before crossing is
(A) 2.75
(B) 3.75
(C) 4.75
(D) 5.75


Answer: (B)

Explanation: As the two cars are moving towards each other, their relative speed will be = 15+30 = 45 kmph.
The distance between them 5 minutes before crossing will be equal to the distance traveled by their relative speed in 5 minutes, i.e.
Required distance = Relative speed (in km per min) * time (in minute) = (45/60)*5 = 3.75 km.

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