QA – Placement Quizzes | Progressions | Question 12

Calculate the sum of given series: log₁₀10 + log₁₀10² + … + log₁₀10ⁿ

(A)

(B)

(C)

(D)

Answer: (D)

Explanation:

Rewriting the expression as 1 + 2 + … + n We know, sum of n natural numbers is given by n*(n+1)/2 = (n²+n)/2

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