log₁₀10 + log₁₀10² + … + log₁₀10ⁿ
(A) n² + 1
(B) n² – 1
(C) [(n² + n)/2] * [(n(n+1))/3]
(D) (n² + n)/2


Answer: (D)

Explanation: Rewriting the expression as
1 + 2 + … + n
We know, sum of n natural numbers is given by n*(n+1)/2 = (n²+n)/2

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