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QA – Placement Quizzes | Progressions | Question 12

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  • Last Updated : 16 Sep, 2021
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Calculate the sum of given series: log1010 + log10102 + … + log1010n


\\n^2 + 1


\\n^2- 1


\\[(n^2+ n)/2] * [(n(n+1))/3]


\\(n^2+ n)/2

Answer: (D)


Rewriting the expression as 1 + 2 + … + n We know, sum of n natural numbers is given by n*(n+1)/2 = (n2+n)/2

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