QA – Placement Quizzes | Progressions | Question 12
Calculate the sum of given series: log1010 + log10102 + … + log1010n
(A)
(B)
(C)
![\\[(n^2+ n)/2] * [(n(n+1))/3]](https://www.geeksforgeeks.org/wp-content/ql-cache/quicklatex.com-9d3f5eadf25a810b16f41c9aa7d6263a_l3.png "Rendered by QuickLaTeX.com")
(D)
Answer: (D)
Explanation:
Rewriting the expression as 1 + 2 + … + n We know, sum of n natural numbers is given by n*(n+1)/2 = (n2+n)/2
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