What is the largest number which divides 26, 47, 84 to leave remainders 2, 3, 0 respectively ?
(A) 4
(B) 6
(C) 8
(D) 1
Answer: (A)
Explanation: 26 – 2 = 24
47 – 3 = 44
84 – 0 = 84
The number divides 26, 47, 84 to leave remainders 2, 3, 0 respectively.
=> The number should divide 24, 44, 84 completely.
HCF (24, 44, 84) = 4
Hence, 4 is the required number.
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