QA – Placement Quizzes | Numbers, LCM and HCF | Question 1
What could be the maximum value of Y in the following equation given that neither of X, Y, Z is zero?
5X8 + 3Y4 + 2Z1 = 1103
1 1 <- CARRY
5 X 8
+ 3 Y 4
+ 2 Z 1
11 0 3
Clearly, X + Y + Z + 1 = 10
=> X + Y + Z = 9
Now, since neither of X, Y, Z can be zero, the value of Y will be maximum when X = Z = 1.
=> Max Y = 7
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