# QA – Placement Quizzes | Mixtures and Alligation | Question 7

Two solutions S1 and S2 contain whisky and soda in the ratio 2 : 5 and 6 : 7 respectively. In what ratio these solutions be mixed to get a new solution S3,  containing whisky and soda in the ratio 5 : 8 ?
(A) 7:9
(B) 21:5
(C) 23:6
(D) 6:23

Explanation:

```Let the amount taken from S1 be 7x
And amount taken from S2 be 13y

(2x + 6y)/(5x + 7y) = 5/8
16x + 48y = 25x + 35y
9x = 13y
x/y = 13/9

Actual ratios of amounts
= 7x/13y
= (7/13) * (13/9)
= 7/9
```

Please refer Mixture and Alligation for direct formula.

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