A sikanji vendor has two drums of sikanji. The first contains 75% of sikanji. The second contains 50% sikanji. How much sikanji should he mix from each of the drum so as to get twelve litres of sikanji such that the ratio of sikanji to soda is 5 : 3?
(A) 8
(B) 6
(C) 10
(D) 9


Answer: (B)

Explanation: Let x litrs from 1^st drum and 12-x litrs from 2^nd drum are mixed

sikanji from 1^st drum = .75x

soda from 1^st drum = .25x

sikanji from 2^nd drum = .5(12-x)

soda from 2^nd drum = .5(12-x)

total sikanji = .25x+6

total soda = .25x+.5(12-x) = 6-.25x

ratio = (.25x+6)/(6-.25x) = 5/3

.75x+18 = 30-1.25x

2x =12

x=6 sikanji and 6 soda

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