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QA – Placement Quizzes | Mixtures and Alligation | Question 15

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A vessel is filled with a solution of, 3 parts soda and 5 parts rum. How much of the solution must be taken out and replaced with soda so that the solution contains equal amount of sod and rum? (A) 8/5 (B) 2/5 (C) 1/5 (D) 5/8

Answer: (C)

Explanation: Let the total solution = 8 litre. soda in the solution = 3 litre, rum in the solution = 5 litre. Say x Lt of the solution is is taken out and replaced with soda. soda in the new solution =3−(3x/8)+x Quantity of rum in the new mixture =5−(5x/8) soda : rum = 1:1 ⇒3−(3x/8)+x = 5−(5x/8) ⇒x=8/5 if the quantity of the solution is 8 litre, 8/5 litre of the solution needs to be taken out and replaced with soda so that the solution contains equal amount of soda and rum. =>1/5th of the solution needs to be taken out and replaced with soda so that the solution contains equal amount of soda and rum.

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Last Updated : 30 Nov, 2021
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