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# QA – Placement Quizzes | Mixtures and Alligation | Question 15

• Difficulty Level : Hard
• Last Updated : 28 Jun, 2021

A vessel is filled with a solution of, 3 parts soda and 5 parts rum. How much of the solution must be taken out and replaced with soda so that the solution contains equal amount of sod and rum?
(A) 8/5
(B) 2/5
(C) 1/5
(D) 5/8

Explanation: Let the total soution = 8 litre.
soda in the solution = 3 litre,
rum in the solution = 5 litre.

Say x Lt of the solution is is taken out and replaced with soda.
soda in the new solution
=3−(3x/8)+x
Quantity of rum in the new mixture
=5−(5x/8)
soda : rum = 1:1
⇒3−(3x/8)+x = 5−(5x/8)

⇒x=8/5

if the quantity of the solution is 8 litre, 8/5 litre of the solution needs to be taken out and replaced with soda so that the solution contains equal amount of soda and rum.
=>1/5th of the solution needs to be taken out and replaced with soda so that the solution contains equal amount of soda and rum.

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