# QA – Placement Quizzes | Mixtures and Alligation | Question 15

A vessel is filled with a solution of, 3 parts soda and 5 parts rum. How much of the solution must be taken out and replaced with soda so that the solution contains equal amount of sod and rum?

**(A)** 8/5

**(B)** 2/5

**(C)** 1/5

**(D)** 5/8

**Answer:** **(C)** **Explanation:** Let the total soution = 8 litre.

soda in the solution = 3 litre,

rum in the solution = 5 litre.

Say x Lt of the solution is is taken out and replaced with soda.

soda in the new solution

=3−(3x/8)+x

Quantity of rum in the new mixture

=5−(5x/8)

soda : rum = 1:1

⇒3−(3x/8)+x = 5−(5x/8)

⇒x=8/5

if the quantity of the solution is 8 litre, 8/5 litre of the solution needs to be taken out and replaced with soda so that the solution contains equal amount of soda and rum.

=>1/5^{th} of the solution needs to be taken out and replaced with soda so that the solution contains equal amount of soda and rum.

Quiz of this Question

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