# QA – Placement Quizzes | Mensuration 3D | Question 6

A hemispherical bowl is filled to the brim with a beverage. The contents of the bowl are transferred into a cylindrical vessel whose radius is 50% more than its height. If the diameter is same for both the bowl and the cylinder, the volume of the beverage in the cylindrical vessel is:
(A) 66.66%
(B) 78.50%
(C) 100%
(D) More than 100% (i.e., some liquid will be left in the bowl)

Explanation: Let the height of the vessel be h. Then,
Radius of the bowl = h/2
Radius of the vessel = h/2
And,
Volume of the bowl = 2/3 * Pi * (h/2)^3 = 1/12 * Pi * h^3
Volume of the vessel = Pi * (h/2)^2 * h = 1/4 * Pi * h^3
As the volume of the vessel is 3 times more than that of the bowl, it can contain 100% of the beverage.

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