Open In App
Related Articles

QA – Placement Quizzes | Mensuration 2D | Question 14

Improve
Improve
Improve
Like Article
Like
Save Article
Save
Report issue
Report
The sides of a triangle are 6 cm, 11 cm and 15 cm. The radius of its in-circle is: (A) 3*(2)^0.5 (B) (4/5)*(2)^0.5 (C) (5/4)*(2)^0.5 (D) 6*(2)^0.5

Answer: (C)

Explanation: Let a, b, c be the sides of the triangle. Then, we know Semi-perimeter = 1/2 * (a + b + c) = 1/2 * (6 + 11 + 15) = 16 cm. Area = [s*(s-a)*(s-b)*(s-c)]^0.5 = [16*10*5*1]^0.5 = 20(2)^0.5 cm^2. Therefore, Radius of in-circle = Area/Semi-perimeter = 20(2)^0.5 / 16 = (5/4)*(2)^0.5 cm.

Quiz of this Question
Please comment below if you find anything wrong in the above post

Last Updated : 28 Jun, 2021
Like Article
Save Article
Previous
Next
Share your thoughts in the comments
Similar Reads