QA – Placement Quizzes | Algebra | Question 14

A total of 324 coins of 20 paise and 25 paise make a sum of Rs 71. The number of 25-paise coins is:
(A) 104
(B) 120
(C) 128
(D) 124


Answer: (D)

Explanation: Let the number of 20-paise coins be x and the number of 25-paise coins be y. Then,
x + y = 324 (equation 1)
And,
x/5 + y/4 = 71
4x + 5y = 71*20 (Multiplying by 20 on both sides)
Substituting the value of x from equation 1, we get
4(324-y) + 5y = 71*20
1296 – 4y + 5y = 1420
y = 124.

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