Skip to content
Related Articles

Related Articles

Improve Article

QA – Placement Quizzes | Age | Question 4

  • Difficulty Level : Medium
  • Last Updated : 28 Jun, 2021

The age of a father was 4 times his son’s age 8 years back. After 8 years, the father will be twice as old as his son. Find out the present ages of father and son.
(A) 16 and 40 years
(B) 14 and 45 years
(C) 10 and 42 years
(D) 13 and 41 years


Answer: (A)

Explanation: Let the son be x years old and the father be y years old. Then,
y-8 = 4(x-8) and y+8 = 2(x+8).
Subtracting the first equation from the second, we get
(y+8) – (y-8) = (2x+16) – (4x-32)
⇒ 16 = -2x + 48
⇒ 2x = 32 ⇒ x = 16.
But, y-8 = 4(x-8). So,
y = 4(x-8) + 8 = 40.
Therefore, the present ages are 16 and 40 years.

Quiz of this Question
Please comment below if you find anything wrong in the above post

My Personal Notes arrow_drop_up
Recommended Articles
Page :