# QA – Placement Quizzes | Age | Question 4

The age of a father was 4 times his son’s age 8 years back. After 8 years, the father will be twice as old as his son. Find out the present ages of father and son.**(A)** 16 and 40 years**(B)** 14 and 45 years**(C)** 10 and 42 years**(D)** 13 and 41 years**Answer:** **(A)****Explanation:** Let the son be x years old and the father be y years old. Then,

y-8 = 4(x-8) and y+8 = 2(x+8).

Subtracting the first equation from the second, we get

(y+8) – (y-8) = (2x+16) – (4x-32)

⇒ 16 = -2x + 48

⇒ 2x = 32 ⇒ x = 16.

But, y-8 = 4(x-8). So,

y = 4(x-8) + 8 = 40.

Therefore, the present ages are 16 and 40 years.

Quiz of this Question

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