# Python3 Program to Check if a string can be formed from another string by at most X circular clockwise shifts

Given an integer X and two strings S1 and S2, the task is to check that string S1 can be converted to the string S2 by shifting characters circular clockwise atmost X times.

Input: S1 = “abcd”, S2 = “dddd”, X = 3
Output: Yes
Explanation:
Given string S1 can be converted to string S2 as-
Character “a” – Shift 3 times – “d”
Character “b” – Shift 2 times – “d”
Character “c” – Shift 1 times – “d”
Character “d” – Shift 0 times – “d”

Input: S1 = “you”, S2 = “ara”, X = 6
Output: Yes
Explanation:
Given string S1 can be converted to string S2 as –
Character “y” – Circular Shift 2 times – “a”
Character “o” – Shift 3 times – “r”
Character “u” – Circular Shift 6 times – “a”

Approach: The idea is to traverse the string and for each index and find the difference between the ASCII values of the character at the respective indices of the two strings. If the difference is less than 0, then for a circular shift, add 26 to get the actual difference. If for any index, the difference exceeds X, then S2 can’t be formed from S1, otherwise possible.
Below is the implementation of the above approach:

## Python3

 `# Python3 implementation to check ` `# that the given string can be ` `# converted to another string  ` `# by circular clockwise shift ` ` `  `# Function to check that the  ` `# string s1 can be converted ` `# to s2 by clockwise circular ` `# shift of all characters of  ` `# str1 atmost X times ` `def` `isConversionPossible(s1, s2, x): ` `    ``n ``=` `len``(s1) ` `    ``s1 ``=` `list``(s1) ` `    ``s2 ``=` `list``(s2) ` `     `  `    ``for` `i ``in` `range``(n): ` `         `  `        ``# Difference between the  ` `        ``# ASCII numbers of characters ` `        ``diff ``=` `ord``(s2[i]) ``-` `ord``(s1[i]) ` `         `  `        ``# If both characters  ` `        ``# are the same ` `        ``if` `diff ``=``=` `0``: ` `            ``continue` `         `  `        ``# Condition to check if the  ` `        ``# difference less than 0 then ` `        ``# find the circular shift by  ` `        ``# adding 26 to it ` `        ``if` `diff < ``0``: ` `            ``diff ``=` `diff ``+` `26` `        ``# If difference between  ` `        ``# their ASCII values ` `        ``# exceeds X ` `        ``if` `diff > x: ` `            ``return` `False` `     `  `    ``return` `True` `     `  ` `  `# Driver Code ` `if` `__name__ ``=``=` `"__main__"``: ` `    ``s1 ``=` `"you"` `    ``s2 ``=` `"ara"` `    ``x ``=` `6` `     `  `    ``# Function Call ` `    ``result ``=` `isConversionPossible(s1, s2, x) ` `     `  `    ``if` `result: ` `        ``print``(``"YES"``) ` `    ``else``: ` `        ``print``(``"NO"``) `

Output:

`YES`

Time Complexity:O(N),N=Length(S1)

Auxiliary Space:O(1)

Please refer complete article on Check if a string can be formed from another string by at most X circular clockwise shifts for more details!

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