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Python | Ways to split a string in different ways

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  • Difficulty Level : Medium
  • Last Updated : 22 Jun, 2022
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The most common problem we have encountered in Python is splitting a string by a delimiter, But in some cases we have to split in different ways to get the answer. In this article, we will get substrings obtained by splitting string in different ways. Examples:

Input : Paras_Jain_Moengage_best Output : [‘Paras’, ‘Paras_Jain’, ‘Paras_Jain_Moengage’, ‘Paras_Jain_Moengage_best’] Input : chunky_2808_GFG_Codechef Output : [‘chunky’, ‘chunky_2808’, ‘chunky_2808_GFG’, ‘chunky_2808_GFG_Codechef’]

Below are some ways to do the task.

Method #1: Using Iteration 

Python3




# Python code to split string in substring manner
 
# Input initialisation
Input = "Geeks_for_geeks_is_best"
 
# Split initialise
split_string = Input.split('_')
 
# Output list initialise
Output = []
 
# Iteration
for a in range(len(split_string)):
    temp = split_string[:a + 1]
    temp = "_".join(temp)
    Output.append(temp)
 
# print output
print(Output)

Output:[‘Geeks’, ‘Geeks_for’, ‘Geeks_for_geeks’, ‘Geeks_for_geeks_is’, ‘Geeks_for_geeks_is_best’]

Method 2: Using Itertools 

Python3




# Python code to split string in substring manner
 
# Importing
from itertools import accumulate
 
# Input initialisation
Input = "Geeks_for_geeks_is_best"
 
# Using accumulate
Output = [*accumulate(Input.split('_'), lambda temp1, temp2 :
                                   '_'.join([temp1, temp2])), ]
 
# Printing output
print(Output)

Output:[‘Geeks’, ‘Geeks_for’, ‘Geeks_for_geeks’, ‘Geeks_for_geeks_is’, ‘Geeks_for_geeks_is_best’]

Method#3 : Using re module and string slicing

Python3




# Python code to split string in substring manner
# Importing
import re
 
# Input initialisation
Input = "Geeks_for_geeks_is_best"
 
# Using re module with string slicing to generate substring
ans = []
for i in re.finditer("(_)", Input):
    temp = Input[:i.span()[0]]
    ans.append(temp)
     
# inserting last substring
ans.append(Input)
 
# Printing output
print(ans)

Output:

['Geeks', 'Geeks_for', 'Geeks_for_geeks', 'Geeks_for_geeks_is', 'Geeks_for_geeks_is_best']

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