# Python – Ways to print longest consecutive list without considering duplicates element

• Last Updated : 10 Sep, 2021

Given, a list of Numbers, the task is to print the longest consecutive (Strictly) list, without considering duplicate elements. If there is more than one answer, print anyone. These type of problem are quite common while working on some web development projects in Django or flask.

Below are some ways to solve the above task.

Note : If there are multiple answers, print anyone

Input:
[1, 2, 3, 5, 6, 6, 7, 9, 10, 11, 13, 14, 15, 16, 16, 17, 18, 20, 21]
Output:
[13, 14, 15, 16]
Explanation :
Original list = [1, 2, 3, 5, 6, 6, 7, 9, 10, 11, 13, 14, 15, 16, 16, 17, 18, 20, 21]
Calculated list = [13, 14, 15, 16, 16, ]
Unique elements = [13, 14, 15, 16, ]

Method 1: Using Iteration
The basic method that comes to mind while performing this operation is the naive method of printing longest consecutive list.

## Python3

 `# Python code to print longest consecutive list.` `# Input list initialization``Input` `=` `[``12``, ``13``, ``14``, ``17``, ``18``, ``23``, ``24``, ``25``, ``25``, ``26``, ``27``]` `# Output list initialization``Output ``=` `[]``temp ``=` `[]``last ``=` `-``1` `# Iteration``for` `elem ``in` `Input``:``    ``if` `elem ``-` `last ``=``=` `1``:``        ``temp.append(last)``    ``else``:``        ``temp.append(last)``        ``Output.append(temp)``        ``temp ``=` `[]``    ``last ``=` `elem` `ans ``=` `[]``most ``=` `0` `for` `elem ``in` `Output:``    ``if` `len``(elem)> most:``        ``most ``=` `len``(elem)``        ``ans ``=` `elem``        ` `# Printing output``print``(``"Initial List is"``)``print``(``Input``)``print``(``"Longest Consecutive list is :"``)``print``(ans)`

Output:

```Initial List is
[12, 13, 14, 17, 18, 23, 24, 25, 25, 26, 27]
Longest Consecutive list is :
[23, 24, 25]```

Method 2: Using groupby and zip
Using Groupby and zip is the most elegant way to print the longest consecutive list.

## Python3

 `# Python code to print longest consecutive list.` `# Importing``from` `itertools ``import` `groupby` `# List Initialization``Input` `=` `[``1``, ``2``, ``3``, ``5``, ``6``, ``6``, ``7``, ``9``, ``10``, ``11``, ``13``, ``14``, ``15``, ``16``, ``16``, ``17``, ``18``, ``20``, ``21``]` `# Using zip``z ``=` `zip``(``Input``, ``Input``[``1``:])` `# Using groupby``lis ``=` `[``list``(y) ``for` `i, y ``in` `groupby(z, key ``=` `lambda` `x: (x[``1``] ``-` `x[``0``]) ``=``=` `1``)]` `# Taking max according to keylength``out ``=` `max``(lis, key ``=` `len``)` `# Output list Initialization``output ``=` `[]` `for` `elem ``in` `out:``    ``output.append(elem[``0``])``    ``output.append(elem[``1``])` `# Converting to set``output ``=` `list``(``set``(output))` `# Sorting output``output.sort()` `# Printing answer``print``(``"Initial list is "``)``print``(``Input``)``print``(``"Longest Consecutive list is:"``)``print``(output)`

Output:

```Initial list is
[1, 2, 3, 5, 6, 6, 7, 9, 10, 11, 13, 14, 15, 16, 16, 17, 18, 20, 21]
Longest Consecutive list is:
[13, 14, 15, 16]```

My Personal Notes arrow_drop_up