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Python | Unique pairs in list
• Last Updated : 05 Sep, 2019

Sometimes, while working with python list, we can have a binary matrix ( Nested list having 2 elements ). And we can have a problem in which we need to find the uniqueness of a pair. A pair is unique irrespective of order, it doesn’t appear again in list. Let’s discuss certain way in which this task can be performed.

Method : Using `frozenset() + Counter()` + list comprehension
The combination of above functions can perform this task. The `frozenset()` is used for ignoring the ordering, `Counter()` is used to perform the task of checking the uniqueness and iteration is done using list comprehension.

 `# Python3 code to demonstrate working of ` `# Unique pairs in list ` `# using frozenset() + Counter() + list comprehension ` `from` `collections ``import` `Counter ` ` `  `# initialize list ` `test_list ``=` `[[``5``, ``6``], [``9``, ``8``], [``8``, ``9``], [``1``, ``4``], [``6``, ``5``], [``10``, ``1``]] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# Unique pairs in list ` `# using frozenset() + Counter() + list comprehension ` `temp ``=` `Counter(``frozenset``(ele) ``for` `ele ``in` `test_list) ` `res ``=` `[temp[``frozenset``(ele)] ``=``=` `1` `for` `ele ``in` `test_list] ` ` `  `# printing result ` `print``(``"The Unique status of elements is "` `+` `str``(res)) `

Output :

```The original list is : [[5, 6], [9, 8], [8, 9], [1, 4], [6, 5], [10, 1]]
The Unique status of elements is [False, False, False, True, False, True]
```

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