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Python – Tuple value product in dictionary
• Last Updated : 29 Dec, 2019

Sometimes, while working with data, we can have a problem in which we need to find the product of tuple elements that are received as values of dictionary. We may have a problem to get index wise product. Letâ€™s discuss certain ways in which this particular problem can be solved.

Method #1 : Using `tuple() + loop + zip() + values()`
The combination of above methods can be used to perform this particular task. In this, we just
zip together equi index values extracted by values() using zip(). Then find product using respective function. Finally result is returned as index wise product as a tuple.

 `# Python3 code to demonstrate working of``# Dictionary Tuple Values Product``# Using tuple() + loop + zip() + values()`` ` `# getting Product``def` `prod(val) :``    ``res ``=` `1` `    ``for` `ele ``in` `val:``        ``res ``*``=` `ele``    ``return` `res `` ` `# Initializing dictionary``test_dict ``=` `{``'gfg'` `: (``5``, ``6``, ``1``), ``'is'` `: (``8``, ``3``, ``2``), ``'best'` `: (``1``, ``4``, ``9``)}`` ` `# printing original dictionary``print``(``"The original dictionary is : "` `+` `str``(test_dict))`` ` `# Dictionary Tuple Values Product``# Using tuple() + loop + zip() + values()``res ``=` `tuple``(prod(x) ``for` `x ``in` `zip``(``*``test_dict.values()))`` ` `# printing result``print``(``"The product from each index is : "` `+` `str``(res))`
Output :
```The original dictionary is : {'gfg': (5, 6, 1), 'is': (8, 3, 2), 'best': (1, 4, 9)}
The product from each index is : (40, 72, 18)
```

Method #2 : Using `tuple() + map() + values()`
This is yet another way in which this task can be performed. The difference is that we use map() instead of loop.

 `# Python3 code to demonstrate working of``# Dictionary Tuple Values Product``# Using tuple() + map() + values()`` ` `# getting Product``def` `prod(val) :``    ``res ``=` `1` `    ``for` `ele ``in` `val:``        ``res ``*``=` `ele``    ``return` `res `` ` `# Initializing dictionary``test_dict ``=` `{``'gfg'` `: (``5``, ``6``, ``1``), ``'is'` `: (``8``, ``3``, ``2``), ``'best'` `: (``1``, ``4``, ``9``)}`` ` `# printing original dictionary``print``(``"The original dictionary is : "` `+` `str``(test_dict))`` ` `# Dictionary Tuple Values Product``# Using tuple() + map() + values()``temp ``=` `[]``for` `sub ``in` `test_dict.values():``    ``temp.append(``list``(sub))``res ``=` `tuple``(``map``(prod, temp))`` ` `# printing result``print``(``"The product from each index is : "` `+` `str``(res))`
Output :
```The original dictionary is : {'gfg': (5, 6, 1), 'is': (8, 3, 2), 'best': (1, 4, 9)}
The product from each index is : (40, 72, 18)
```

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