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Python | Truncate a list
  • Last Updated : 04 Jan, 2019

Sometimes there is a requirement to restrict the list size to a particular number and remove all the elements from list which occur after a certain number as decided as list size. This is a useful utility for web development using Python. Let’s discuss certain ways in which this can be performed.

Method #1 : Using pop()
pop function can be repeated a number of times till size of the list reaches the threshold required as the size of the list. This uses a whole loop and hence is comparatively tedious.




# Python3 code to demonstrate 
# to truncate list using pop()
  
# initializing list  
test_list = [1, 4, 5, 6, 7, 3, 8, 9, 10]
  
# printing original list
print ("The original list is : " + str(test_list))
  
# size desired
k = 5
  
# using pop()
# to truncate list 
n = len(test_list)
for i in range(0, n - k ):
    test_list.pop()
  
# printing result
print ("The truncated list is : " +  str(test_list))
Output:
The original list is : [1, 4, 5, 6, 7, 3, 8, 9, 10]
The truncated list is : [1, 4, 5, 6, 7]

 
Method #2 : Using del + list slice
del operator can be used to delete all the elements that appear after the specific index, which is handled by the list slicing technique.




# Python3 code to demonstrate 
# to truncate list 
# using del + list slicing
  
# initializing list  
test_list = [1, 4, 5, 6, 7, 3, 8, 9, 10]
  
# printing original list
print ("The original list is : " + str(test_list))
  
# size desired
k = 5
  
# using del + list slicing
# to truncate list 
del test_list[5:]
  
# printing result
print ("The truncated list is : " +  str(test_list))
Output:



The original list is : [1, 4, 5, 6, 7, 3, 8, 9, 10]
The truncated list is : [1, 4, 5, 6, 7]

 
Method #3 : Using list slicing
In this method, we just slice the first K elements and ignore all the elements that occur after K elements. This is most pythonic and recommended method to perform this task.




# Python3 code to demonstrate 
# to truncate list 
# using list slicing
  
# initializing list  
test_list = [1, 4, 5, 6, 7, 3, 8, 9, 10]
  
# printing original list
print ("The original list is : " + str(test_list))
  
# size desired
k = 5
  
# using list slicing
# to truncate list 
res = test_list[0 : 5]
  
# printing result
print ("The truncated list is : " +  str(res))
Output:
The original list is : [1, 4, 5, 6, 7, 3, 8, 9, 10]
The truncated list is : [1, 4, 5, 6, 7]

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