# Python | Test list element similarity

Given a list, your task is to determine the list is K percent same i.e has element that is populated more than K % times.

Given below are few methods to solve the task.
Method #1 Using collections.Counter

 `# Python3 code to demonstrate ` `# to check whether the list ` `# K percent same or not ` `from` `collections ``import` `Counter ` ` `  `# initializing list ` `ini_list1 ``=` `[``1``, ``2``, ``3``, ``1``, ``1``, ``1``, ``1``, ``1``, ``3``, ``2``] ` ` `  `# printing initial list ` `print` `(``"Initial list"``, ini_list1) ` ` `  `# initializing K ` `K ``=` `60` ` `  `# code to check whether list is K % same or not ` `i, freq ``=` `Counter(ini_list1).most_common(``1``)[``0``] ` ` `  `if` `len``(ini_list1)``*``(K ``/` `100``) <``=` `freq: ` `    ``print``(``"True"``) ` `else``: ` `    ``print``(``"False"``) `

Output:

```Initial list [1, 2, 3, 1, 1, 1, 1, 1, 3, 2]
True
```

Method #2: Using dictionary and its values

 `# Python3 code to demonstrate ` `# to check whether the list ` `# K percent same or not ` `from` `collections ``import` `Counter, defaultdict ` ` `  `# initializing list ` `ini_list1 ``=` `[``1``, ``2``, ``3``, ``1``, ``1``, ``1``, ``1``, ``1``, ``3``, ``2``] ` ` `  `# printing initial list ` `print` `(``"Initial list"``, ini_list1) ` ` `  `# initializing K ` `K ``=` `60` ` `  `# code to check whether list is K % same or not ` `freq ``=` `defaultdict(``int``) ` `for` `x ``in` `ini_list1: ` `    ``freq[x] ``+``=` `1` `freq ``=` `freq.values() ` `if` `max``(freq) >``=` `(K ``/` `100``) ``*` `sum``(freq): ` `    ``print` `(``"True"``) ` `else``: ` `    ``print` `(``"False"``) `

Output:

```initial list [1, 2, 3, 1, 1, 1, 1, 1, 1, 1]
True
```

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