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Python – Test Kth index in Dictionary value list
• Last Updated : 10 May, 2020

Sometimes, while working with Python dictionaries, we can have a problem in which we need to test if througout the dictionary, the kth index of all values in dictionary is equal to N. This kind of problem can occur in web development domain. Let’s discuss certain ways in which this problem can be solved.

Input : test_dict = {‘Gfg’ : [10, 4, 8, 17], ‘best’ : [90, 4]}
Output : True

Input : test_dict = {‘Gfg’ : [10, 7]}
Output : False

Method #1 : Using loop + `items()`
The combination of above functions can be used to solve this problem. In this, we check for all items of dictionary using items() and loop is used to iterate for dictionary keys and testing for equality.

 `# Python3 code to demonstrate working of ``# Test Kth index in Dictionary value list``# Using  items() + loop`` ` `# initializing dictionary``test_dict ``=` `{``'Gfg'` `: [``1``, ``4``, ``8``], ``'is'` `: [``8``, ``4``, ``2``], ``'best'` `: [``7``, ``4``, ``9``]}`` ` `# printing original dictionary``print``(``"The original dictionary : "` `+` `str``(test_dict))`` ` `# initializing K ``K ``=` `2`` ` `# initializing N ``N ``=` `4`` ` `# Test Kth index in Dictionary value list``# Using  items() + loop``res ``=` `True``for` `key, val ``in` `test_dict.items():``    ``if` `val[K ``-` `1``] !``=` `N:``        ``res ``=` `False`` ` `# printing result ``print``(``"Are all Kth index equal to N : "` `+` `str``(res)) `
Output :

```The original dictionary : {'is': [8, 4, 2], 'best': [7, 4, 9], 'Gfg': [1, 4, 8]}
Are all Kth index equal to N : True
```

Method #2 : Using `all()` + generator expression
The combination of above functions can also be used to solve this problem. In this, we use all() to test for equality of all elements to N.

 `# Python3 code to demonstrate working of ``# Test Kth index in Dictionary value list``# Using all() + generator expression`` ` `# initializing dictionary``test_dict ``=` `{``'Gfg'` `: [``1``, ``4``, ``8``], ``'is'` `: [``8``, ``4``, ``2``], ``'best'` `: [``7``, ``4``, ``9``]}`` ` `# printing original dictionary``print``(``"The original dictionary : "` `+` `str``(test_dict))`` ` `# initializing K ``K ``=` `2`` ` `# initializing N ``N ``=` `4`` ` `# Test Kth index in Dictionary value list``# Using all() + generator expression``res ``=` `all``([val[K ``-` `1``] ``=``=` `N ``for` `idx, val ``in` `test_dict.items()])`` ` `# printing result ``print``(``"Are all Kth index equal to N : "` `+` `str``(res)) `
Output :
```The original dictionary : {'is': [8, 4, 2], 'best': [7, 4, 9], 'Gfg': [1, 4, 8]}
Are all Kth index equal to N : True
```

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