Python – Test K in Range

Given a List, Test if all elements in given range is equal to K.

Input : test_list = [2, 3, 4, 4, 4, 4, 6, 7, 8, 2], i, j = 2, 5, K = 4 
Output : True 
Explanation : All elements in range are 4.

Input : test_list = [2, 3, 4, 9, 4, 4, 6, 7, 8, 2], i, j = 2, 5, K = 4 
Output : False 
Explanation : All elements in range are not 4. 

Method #1 : Using any()

In this, we check for negation of logic to be found, check if we get any element other than K, we return the negation of truth value to get actual result.



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# Python3 code to demonstrate working of 
# Test K in Range
# Using any()
  
# initializing list
test_list = [2, 3, 4, 4, 4, 4, 6, 7, 8, 2]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing Range
i, j = 2, 5
  
# initializing K 
K = 4
  
# any() to check if any element other than K present 
# negation gives result 
res = not any(test_list[idx] != K for idx in range(i, j + 1))
  
# printing result 
print("Are all elements in range K ? : " + str(res))

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Output

The original list is : [2, 3, 4, 4, 4, 4, 6, 7, 8, 2]
Are all elements in range K ? : True

Method #2 : Using all() 

In this, we check for all elements to be K in required range of list using all().

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# Python3 code to demonstrate working of 
# Test K in Range
# Using all() 
  
# initializing list
test_list = [2, 3, 4, 4, 4, 4, 6, 7, 8, 2]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing Range
i, j = 2, 5
  
# initializing K 
K = 4
  
# all() to check all elements to be K 
res = all(test_list[idx] == K for idx in range(i, j + 1))
  
# printing result 
print("Are all elements in range K ? : " + str(res))

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Output

The original list is : [2, 3, 4, 4, 4, 4, 6, 7, 8, 2]
Are all elements in range K ? : True

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