Python – Test if Kth character is digit in String
Given a String, check if Kth index is a digit.
Input : test_str = ‘geeks9geeks’, K = 5
Output : True
Explanation : 5th idx element is 9, a digit, hence True.
Input : test_str = ‘geeks9geeks’, K = 4
Output : False
Explanation : 4th idx element is s, not a digit, hence False.
Method #1 : Using in operator
In this, we create a string of numerics and then use in operator to check if Kth digit lies in that numeric string.
Python3
# Python3 code to demonstrate working of# Test if Kth character is digit in String# Using in operator# initializing stringtest_str = 'geeks4geeks'# printing original Stringprint("The original string is : " + str(test_str))# initializing KK = 5# checking if Kth digit is string# getting numeric strnum_str = "0123456789"res = test_str[K] in num_str# printing resultprint("Is Kth element String : " + str(res)) |
The original string is : geeks4geeks Is Kth element String : True
Method #2 : Using isdigit()
In this, we use inbuilt Py. function to solve this problem, and check if Kth element is digit.
Python3
# Python3 code to demonstrate working of# Test if Kth character is digit in String# Using isdigit()# initializing stringtest_str = 'geeks4geeks'# printing original Stringprint("The original string is : " + str(test_str))# initializing KK = 5# isdigit checks for digitres = test_str[K].isdigit()# printing resultprint("Is Kth element String : " + str(res)) |
The original string is : geeks4geeks Is Kth element String : True
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