Python – Test if K occurs N consecutive times

Sometimes, while working with Python list, we can have a problem in which we need to check if a particular number occurs N consecutive times. This can have application in many domains including day-day programming. Lets discuss certain ways in which this task can be performed.

Method #1 : Using list comprehension
This is a way in which this task can be performed. In this, we iterate the list and check for occurrence in list using multiplication operator in a one liner.

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# Python3 code to demonstrate 
# Test if K occurs N consecutive times
# using list comprehension
  
# Initializing list
test_list = [1, 3, 4, 4, 4, 3, 3, 2, 2, 1]
  
# printing original list
print("The original list is : " + str(test_list))
  
# Initializing K 
K = 4
  
# Initializing N 
N = 3
  
# Test if K occurs N consecutive times
# using list comprehension
res = [K] * N in (test_list[i : i + N] for i in range(len(test_list) - N))
  
# printing result 
print ("Does K occur N consecutive times ? : " + str(res))

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Output :

The original list is : [1, 3, 4, 4, 4, 3, 3, 2, 2, 1]
Does K occur N consecutive times ? : True

 

Method #2 : Using lambda + join()
This is yet another way to perform this task. In this, we perform the task of checking for consecution using lambda and join() is used to get the elements groups that are consecutive.



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# Python3 code to demonstrate 
# Test if K occurs N consecutive times
# using lambda + join()
  
# Initializing list
test_list = [1, 3, 4, 4, 4, 3, 3, 2, 2, 1]
  
# printing original list
print("The original list is : " + str(test_list))
  
# Initializing K 
K = 4
  
# Initializing N 
N = 3
  
# Test if K occurs N consecutive times
# using lambda + join()
res = bool(lambda ele: str(K) * N in ''.join(str(num) for num in test_list))
  
# printing result 
print ("Does K occur N consecutive times ? : " + str(res))

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Output :

The original list is : [1, 3, 4, 4, 4, 3, 3, 2, 2, 1]
Does K occur N consecutive times ? : True

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