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Python | Test if any list element returns true for condition
  • Last Updated : 27 Sep, 2019

Sometimes, while coding in Python, we can have a problem in which we need to filter a list on basis of condition met by any of the element. This can have it’s application in web development domain. Let’s discuss a shorthand in which this task can be performed.

Method : Using any() + list comprehension
The simplest way and shorthand to solve this problem is to combine the functionalities of inbuilt any() and list comprehension for rendering condition logic and list iteration. The any() returns true if any of the list element matches the condition.




# Python3 code to demonstrate working of
# Test if any list element returns true for condition
# Using any() + list comprehension
  
# initializing list
test_list = [6, 4, 8, 9, 10]
  
# printing list
print("The original list : " + str(test_list))
  
# Test if any list element returns true for condition
# Using any() + list comprehension
res = any(x % 5 for x in test_list)
  
# Printing result
print("Does list contain any element divisible by 5? : " + str(res))
Output :
 
The original list : [6, 4, 8, 9, 10]
Does list contain any element divisible by 5? : True

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