Python – Test if all elements in list are of same type
Sometimes, while working with Python, we can have a problem in which we need to test if all the elements of argument are of same type or not. This can have application in many domains such as data Science and day-day programming. Lets discuss certain ways in which this task can be performed.
Method #1 : Using loop + isinstance()
The combination of above functionalities can be used to perform this task. In this, we test for type using isinstance() and check for all elements if they match same type as of 1st element.
# Python3 code to demonstrate # Test if all elements in list are of same type# using loop + isinstance() # Initializing liststest_list = [5, 6, 2, 5, 7, 9] # printing original listprint("The original list is : " + str(test_list)) # Test if all elements in list are of same type# using loop + isinstance()res = Truefor ele in test_list: if not isinstance(ele, type(test_list[0])): res = False break # printing result print ("Do all elements have same type : " + str(res)) |
Output :
The original list is : [5, 6, 2, 5, 7, 9] Do all elements have same type : True
Method #2 : Using all() + isinstance()
This is yet another way to perform this task. In this, we instead of iterating perform the task in one line using all and instance().
# Python3 code to demonstrate # Test if all elements in list are of same type# using all() + isinstance() # Initializing liststest_list = [5, 6, 2, 5, 7, 9] # printing original listprint("The original list is : " + str(test_list)) # Test if all elements in list are of same type# using all() + isinstance()res = all(isinstance(sub, type(test_list[0])) for sub in test_list[1:]) # printing result print ("Do all elements have same type : " + str(res)) |
Output :
The original list is : [5, 6, 2, 5, 7, 9] Do all elements have same type : True
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