Given a Matrix, test if all columns contain unique elements.
Input : test_list = [[3, 4, 5], [1, 2, 4], [4, 1, 10]]
Output : True
Explanation : 3, 1, 4; 4, 2, 1; 5, 4, 10; All elements are unique in columns.Input : test_list = [[3, 4, 5], [3, 2, 4], [4, 1, 10]]
Output : False
Explanation : 3, 3, 4; 3 repeated twice.
Method #1 : Using loop + set() + len()
In this, we iterate for each column and test for unique elements using set size using len(), if any column is found having a size not equal to the actual list, then the result is flagged off.
Python3
# Python3 code to demonstrate working of # Test if all elements Unique in Matrix Columns # Using loop + set() + len() # initializing list test_list = [[3, 4, 5], [1, 2, 4], [4, 1, 10]] # printing original lists print("The original list is : " + str(test_list)) res = True for idx in range(len(test_list[0])): # getting column col = [ele[idx] for ele in test_list] # checking for all Unique elements if len(list(set(col))) != len(col): res = False break # printing result print("Are all columns Unique : " + str(res)) |
Output:
The original list is : [[3, 4, 5], [1, 2, 4], [4, 1, 10]] Are all columns Unique : True
Method #2 : Using all() + list comprehension
This can be solved in one-liner using all() which checks for all the columns, made using list comprehension, if all columns return True, all() returns true.
Python3
# Python3 code to demonstrate working of # Test if all elements Unique in Matrix Columns # Using loop + set() + len() # initializing list test_list = [[3, 4, 5], [1, 2, 4], [4, 1, 10]] # printing original lists print("The original list is : " + str(test_list)) res = True for idx in range(len(test_list[0])): # getting column col = [ele[idx] for ele in test_list] # checking for all Unique elements if len(list(set(col))) != len(col): res = False break # printing result print("Are all columns Unique : " + str(res)) |
Output:
The original list is : [[3, 4, 5], [1, 2, 4], [4, 1, 10]] Are all columns Unique : True
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