# Python – Sympy Polygon.distance() method

• Last Updated : 01 Aug, 2020

In Sympy, the function Polygon.distance() is used to return the shortest distance between the given polygon and o. If o is a point, then given polygon does not need to be convex. But If o is another polygon then, the given polygon and o must be convex.

```Syntax: Polygon.distance(o)

Parameters:
o:Point or Polygon

Returns: the shortest distance between the given polygon and o.```

Example #1:

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## Python3

 `# import sympy import Point, Polygon``from` `sympy ``import` `Point, Polygon`` ` `# creating points using Point()``p1, p2, p3, p4 ``=` `map``(Point, [(``0``, ``2``), (``0``, ``0``), (``1``, ``0``), (``1``, ``2``)])`` ` `# creating polygon using Polygon()``poly ``=` `Polygon(p1, p2, p3, p4)`` ` `# using distance()``shortestDistance ``=` `poly.distance(Point(``3``, ``5``))`` ` `print``(shortestDistance)`

Output:

`sqrt(13)`

Example #2:

## Python3

 `# import sympy import Point, Polygon, RegularPolygon``from` `sympy ``import` `Point, Polygon, RegularPolygon`` ` `# creating points using Point()``p1, p2 ``=` `map``(Point, [(``0``, ``0``), (``7``, ``5``)])`` ` `# creating polygon using Polygon() and RegularPolygon()``poly ``=` `Polygon(``*``RegularPolygon(p1, ``1``, ``3``).vertices)`` ` `# using distance()``shortestDistance ``=` `poly.distance(p2)`` ` `print``(shortestDistance)`

Output:

`sqrt(61)`

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