# Python | Sympy Plane.are_concurrent() method

• Last Updated : 23 Mar, 2020
In Simpy, the function `Plane.are_concurrent()` is used to check whether the given sequence of planes are concurrent or not. Two or more Planes are concurrent if their intersections are a common line.
```Syntax: Plane.are_concurrent()

Parameters:
planes: sequence of planes

Returns:
True: if they are concurrent, else False
```

Example #1:

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 `# import sympy, Point3D and Plane``from` `sympy ``import` `Point3D, Plane`` ` `# using Plane() ``p1 ``=` `Plane(Point3D(``5``, ``0``, ``0``), normal_vector ``=``(``1``, ``-``1``, ``1``))``p2 ``=` `Plane(Point3D(``0``, ``-``2``, ``0``), normal_vector ``=``(``3``, ``1``, ``1``))`` ` `# using are_concurrent()``areConcurrent ``=` `Plane.are_concurrent(p1, p2)`` ` `print``(areConcurrent)`

Output:

`True`

Example #2:

 `# import sympy, Point3D and Plane``from` `sympy ``import` `Point3D, Plane`` ` `# using Plane() ``p1 ``=` `Plane(Point3D(``5``, ``0``, ``0``), normal_vector ``=``(``1``, ``-``1``, ``1``))``p2 ``=` `Plane(Point3D(``0``, ``-``2``, ``0``), normal_vector ``=``(``3``, ``1``, ``1``))``p3 ``=` `Plane(Point3D(``0``, ``-``1``, ``0``), normal_vector ``=``(``5``, ``-``1``, ``9``))`` ` `# using are_concurrent()``areConcurrent ``=` `Plane.are_concurrent(p1, p2, p3)`` ` `print``(areConcurrent)`

Output:

`False`

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