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# Python | sympy.nT() method

• Last Updated : 02 Aug, 2019

With the help of sympy.nT() method, we can calculate the number of partitions that can have a given number of parts in SymPy.

Syntax: nT(items, k)

Parameters:
items – An integer, a list or a string upon which partitions is to be calculated.
k – An integer specifying the number of parts that the partition should contain.

Returns: Returns the number of partitions that have given number of parts.

Example #1:

 `# import sympy ``from` `sympy ``import` `*` ` ` `items ``=` `"aaa"``k ``=` `2`` ` `print``(``"Value of k = {} and the items are = {}"``.``format``(k, items))``  ` `# Use sympy.nT() method ``partitions ``=` `nT(items, k)  ``     ` `print``(``"Partitions : {}"``.``format``(partitions))  `

Output:

```Value of k = 2 and the items are = aaa
Partitions : 1
```

Example #2:

 `# import sympy ``from` `sympy ``import` `*` ` ` `items ``=` `[``1``, ``3``, ``2``, ``5``, ``4``]``k ``=` `3``print``(``"Value of k = {} and the items are = {}"``.``format``(k, items))``  ` `# Use sympy.nT() method ``partitions ``=` `nT(items, k)  ``     ` `print``(``"Partitions : {}"``.``format``(partitions))  `

Output:

```Value of k = 3 and the items are = [1, 3, 2, 5, 4]
Partitions : 25
```

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