Python | sympy.nP() method
Last Updated :
26 Jul, 2019
With the help of sympy.nP() method, we can calculate the number of permutation of a given length in SymPy.
Syntax: nP(items, k)
Parameter:
items – An integer, a list or a string upon which permutation is to be calculated.
k – An integer specifying the length of the permutation.
Returns: Returns the number of permutation of a given length.
Example #1:
from sympy import *
items = "abca"
k = 3
print ( "Value of k = {} and the items are = {}" . format (k, items))
permutations = nP(items, k)
print ( "Permutation : {}" . format (permutations))
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Output:
Value of k = 3 and the items are = abca
Permutation : 12
Example #2:
from sympy import *
items = [ 2 , 1 , 3 , 5 , 4 ]
k = 3
print ( "Value of k = {} and the items are = {}" . format (k, items))
permutations = nP(items, k)
print ( "Permutation : {}" . format (permutations))
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Output:
Value of k = 3 and the items are = [2, 1, 3, 5, 4]
Permutation : 60
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