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Python | Sympy Line.perpendicular_segment() method

  • Last Updated : 19 Feb, 2020
In Sympy, the function perpendicular_segment() is used to create a perpendicular line segment from a given point to the given line.The endpoints of the segment are p and the
closest point in the line containing self.
Syntax: Line.perpendicular_segment(p)

Parameters:
 p: Point

Returns: 
 segment: Segment

Example #1:




# import sympy and Point, Line
from sympy import Point, Line
  
p1, p2, p3 = Point(0, 0), Point(1, 1), Point(0, 2)
l1 = Line(p1, p2)
  
# using perpendicular_segment() method
perpendicularSegment = l1.perpendicular_segment(p3)
  
print(perpendicularSegment)

Output:

Segment2D(Point2D(0, 2), Point2D(1, 1))

Example #2:




# import sympy and Point3D, Line3D
from sympy import Point3D, Line3D
  
p1, p2, p3 = Point3D(0, 0, 0), Point3D(1, 1, 1), Point3D(0, 2, 0)
ll1 = Line3D(p1, p2)
  
# using perpendicular_segment() method
s1 = l1.perpendicular_segment(p3)
  
perpendicularSegment = l1.perpendicular_segment(p3)
  
print(perpendicularSegment)

Output:

Segment3D(Point3D(0, 2, 0), Point3D(2/3, 2/3, 2/3))

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