Python | Sympy Line.perpendicular_line method

In Sympy, the function perpendicular_line() is used to create a new Line perpendicular to the given linear entity which passes through the given point p. 

Syntax: Line.perpendicular_line(p)

Parameters:
p: Point

Returns:line 

Example #1:

Python3

# import sympy and Point, Line
from sympy import Point, Line

p1, p2, p3 = Point(0, 0), Point(2, 3), Point(-2, 2)

l1 = Line(p1, p2)

# using perpendicular_line() method
l2 = l1.perpendicular_line(p3)

# checking l2 is perpendicular to l1 using is_perpendicular() method
isPerpendicular = l1.is_perpendicular(l2)

print(isPerpendicular)

Output:

True

Example #2:

Python3

# import sympy and Point3D, Line3D
from sympy import Point3D, Line3D

p1, p2, p3 = Point3D(0, 0, 0), Point3D(2, 3, 4), Point3D(-2, 2, 0)

l1 = Line3D(p1, p2)

# using perpendicular_line() method
l2 = l1.perpendicular_line(p3)

# checking l2 is perpendicular to l1 using is_perpendicular() method
isPerpendicular = l2 = l1.is_perpendicular(p3)

print(isPerpendicular)

Output:

True