Python | sympy.is_comparable() method

With the help of sympy.is_comparable() method, we can compute the real number with precision and return True if computed value is real with precision by using sympy.is_comparable() method.

Syntax : sympy.is_comparable()
Return : Return boolean value if real number is computed.

Example #1 :
In this example we can see that by using sympy.is_comparable() method, we are able to evaluate the expression and if computed value is real with precision it will return True else False.



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# import sympy
from sympy import * 
  
x, y, z = symbols('x y z')
  
# Use sympy.is_comparable() method
gfg = (3 * x + 2 * tan(y + I * pi) + log(2 * x)).is_comparable
    
print(gfg)

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Output :

False

Example #2 :

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# import sympy
from sympy import * 
  
x, y, z = symbols('x y z')
  
# Use sympy.is_comparable() method
gfg = (pi / 2).is_comparable
    
print(gfg)

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Output :

True



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