Python | sympy.is_comparable() method
With the help of sympy.is_comparable()
method, we can compute the real number with precision and return True if computed value is real with precision by using sympy.is_comparable()
method.
Syntax : sympy.is_comparable()
Return : Return boolean value if real number is computed.
Example #1 :
In this example we can see that by using sympy.is_comparable()
method, we are able to evaluate the expression and if computed value is real with precision it will return True else False.
from sympy import *
x, y, z = symbols( 'x y z' )
gfg = ( 3 * x + 2 * tan(y + I * pi) + log( 2 * x)).is_comparable
print (gfg)
|
Output :
False
Example #2 :
from sympy import *
x, y, z = symbols( 'x y z' )
gfg = (pi / 2 ).is_comparable
print (gfg)
|
Output :
True
Last Updated :
19 Jul, 2019
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