# Python | sympy.is_comparable() method

With the help of `sympy.is_comparable()` method, we can compute the real number with precision and return True if computed value is real with precision by using `sympy.is_comparable()` method.

Syntax : `sympy.is_comparable()`
Return : Return boolean value if real number is computed.

Example #1 :
In this example we can see that by using `sympy.is_comparable()` method, we are able to evaluate the expression and if computed value is real with precision it will return True else False.

 `# import sympy ` `from` `sympy ``import` `*`  ` `  `x, y, z ``=` `symbols(``'x y z'``) ` ` `  `# Use sympy.is_comparable() method ` `gfg ``=` `(``3` `*` `x ``+` `2` `*` `tan(y ``+` `I ``*` `pi) ``+` `log(``2` `*` `x)).is_comparable ` `   `  `print``(gfg) `

Output :

False

Example #2 :

 `# import sympy ` `from` `sympy ``import` `*`  ` `  `x, y, z ``=` `symbols(``'x y z'``) ` ` `  `# Use sympy.is_comparable() method ` `gfg ``=` `(pi ``/` `2``).is_comparable ` `   `  `print``(gfg) `

Output :

True

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