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Python | sympy.has() method
  • Last Updated : 19 Jul, 2019

With the help of sympy.has() method, we can check if variable is used in that mathematical expression or not and this will return a boolean values by using sympy.has() method.

Syntax : sympy.has(variable)
Return : Return boolean value i.e True or False.

Example #1 :
In this example we can see that by using sympy.has() method, we are able to check the variable is used in the mathematical expression or not.




# import sympy
from sympy import * 
  
x, y, z = symbols('x y z')
  
# Use sympy.has() method
gfg = (3 * x + 2 * tan(y + I * pi) + log(2 * x)).has(x)
    
print(gfg)


Output :

True



Example #2 :




# import sympy
from sympy import * 
  
x, y, z = symbols('x y z')
  
# Use sympy.has() method
gfg = (3 * sin(x) + 2 * tan(y + I * pi)).has(z)
    
print(gfg)


Output :

False

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