Python | sympy.has() method
Last Updated :
19 Jul, 2019
With the help of sympy.has()
method, we can check if variable is used in that mathematical expression or not and this will return a boolean values by using sympy.has()
method.
Syntax : sympy.has(variable)
Return : Return boolean value i.e True or False.
Example #1 :
In this example we can see that by using sympy.has()
method, we are able to check the variable is used in the mathematical expression or not.
from sympy import *
x, y, z = symbols( 'x y z' )
gfg = ( 3 * x + 2 * tan(y + I * pi) + log( 2 * x)).has(x)
print (gfg)
|
Output :
True
Example #2 :
from sympy import *
x, y, z = symbols( 'x y z' )
gfg = ( 3 * sin(x) + 2 * tan(y + I * pi)).has(z)
print (gfg)
|
Output :
False
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