Python | sympy.bernoulli() method
With the help of sympy.bernoulli() method, we can find the Bernoulli number and Bernoulli polynomial in SymPy.
bernoulli(n) -
Syntax: bernoulli(n)
Parameter:
n – It denotes the nth bernoulli number.
Returns: Returns the nth bernoulli number.
Example #1:
from sympy import * n = 4
print ( "Value of n = {}" . format (n))
nth_bernoulli = bernoulli(n)
print ( "Value of nth bernoulli number : {}" . format (nth_bernoulli))
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Output:
Value of n = 4
Value of nth bernoulli number : -1/30
bernoulli(n, k) -
Syntax: bernoulli(n, k)
Parameter:
n – It denotes the order of the bernoulli polynomial.
k – It denotes the variable in the bernoulli polynomial.
Returns: Returns the expression of the bernoulli polynomial or its value.
Example #2:
from sympy import * n = 5
k = symbols( 'x' )
print ( "Value of n = {} and k = {}" . format (n, k))
nth_bernoulli_poly = bernoulli(n, k)
print ( "The nth bernoulli polynomial : {}" . format (nth_bernoulli_poly))
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Output:
Value of n = 5 and k = x
The nth bernoulli polynomial : x**5 - 5*x**4/2 + 5*x**3/3 - x/6
Example #3:
from sympy import * n = 4
k = 3
print ( "Value of n = {} and k = {}" . format (n, k))
nth_bernoulli_poly = bernoulli(n, k)
print ( "The nth bernoulli polynomial value : {}" . format (nth_bell_poly))
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Output:
Value of n = 4 and k = 3
The nth bernoulli polynomial value : 10*x1**2*x3 + 15*x1*x2**2
Last Updated :
14 Jul, 2019
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