Python | Sum of squares in list

Python being the language of magicians can be used to perform many tedious and repetitive tasks in a easy and concise manner and having the knowledge to utilize this tool to the fullest is always useful. One such small application can be finding sum of squares of list in just one line. Let’s discuss certain ways in which this can be performed.

Method #1 : Using reduce() + lambda
The power of lambda functions to perform lengthy tasks in just one line, allows it combined with reduce which is used to accumulate the subproblem, to perform this task as well. Works with only Python 2.

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# Python code to demonstrate  
# sum of squares 
# using reduce() + lambda
  
# initializing list
test_list = [3, 5, 7, 9, 11]
  
# printing original list 
print ("The original list is : " + str(test_list))
  
# using reduce() + lambda
# sum of squares 
res = reduce(lambda i, j: i + j * j, [test_list[:1][0]**2]+test_list[1:])
  
# printing result
print ("The sum of squares of list is : " + str(res))

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Output :



The original list is : [3, 5, 7, 9, 11]
The sum of squares of list is : 285

 

Method #2 : Using map() + sum()
The similar solution can also be obtained using the map function to integrate and sum function to perform the summation of the squared number.

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# Python3 code to demonstrate  
# sum of squares 
# using sum() + max()
  
# initializing list
test_list = [3, 5, 7, 9, 11]
  
# printing original list 
print ("The original list is : " + str(test_list))
  
# using sum() + max()
# sum of squares 
res = sum(map(lambda i : i * i, test_list))
  
# printing result
print ("The sum of squares of list is : " + str(res))

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Output :

The original list is : [3, 5, 7, 9, 11]
The sum of squares of list is : 285


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