Python – Split String on all punctuations

Given a String, Split the String on all the punctuations.

Input : test_str = ‘geeksforgeeks! is-best’
Output : [‘geeksforgeeks’, ‘!’, ‘is’, ‘-‘, ‘best’]
Explanation : Splits on ‘!’ and ‘-‘.

Input : test_str = ‘geek-sfo, rgeeks! is-best’
Output : [‘geek’, ‘-‘, ‘sfo’, ‘, ‘, ‘rgeeks’, ‘!’, ‘is’, ‘-‘, ‘best’]
Explanation : Splits on ‘!’, ‘, ‘ and ‘-‘.

Method : Using regex + findall()

This is one way in which this problem can be solved. In this, we construct appropriate regex and task of segregating and split is done by findall().

Python3

# Python3 code to demonstrate working of
# Split String on all punctuations
# using regex + findall()
import re

# initializing string
test_str = 'geeksforgeeks ! is-best, for @geeks'

# printing original String
print("The original string is : " + str(test_str))

# using findall() to get all regex matches.
res = re.findall( r'\w+|[^\s\w]+', test_str)

# printing result
print("The converted string : " + str(res))

Output

The original string is : geeksforgeeks! is-best, for @geeks
The converted string : ['geeksforgeeks', '!', 'is', '-', 'best', ', ', 'for', '@', 'geeks']

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