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Python | Split nested list into two lists
  • Last Updated : 10 Apr, 2019

Given a nested 2D list, the task is to split the nested list into two lists such that first list contains first elements of each sublists and second list contains second element of each sublists.

Method #1: Using map, zip()

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# Python code to demonstrate
# splitting nested list
# into 2 lists
  
# initialising nested lists
ini_list = [[1, 2], [4, 3], [45, 65], [223, 2]]
  
# printing initial lists
print ("initial list", str(ini_list))
  
# code to split it into 2 lists
res1, res2 = map(list, zip(*ini_list))
  
# printing result
print("final lists", res1, "\n", res2)

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Output:

initial list [[1, 2], [4, 3], [45, 65], [223, 2]]
final lists [1, 4, 45, 223] 
 [2, 3, 65, 2]

 
Method #2: Using list comprehension

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# python code to demonstrate
# splitting nested list
# into 2 lists
  
# initialising nested lists
ini_list = [[1, 2], [4, 3], [45, 65], [223, 2]]
  
# printing initial lists
print ("initial list", str(ini_list))
  
# code to split it into 2 lists
res1 = [i[1] for i in ini_list]
res2 = [i[0] for i in ini_list]
  
# printing result
print("final lists", str(res1), "\n", str(res2))

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Output:



initial list [[1, 2], [4, 3], [45, 65], [223, 2]]
final lists [2, 3, 65, 2] 
 [1, 4, 45, 223]

 
Method #3: Using operator.itemgetter()

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# python code to demonstrate
# splitting nested list
# into 2 lists
  
from operator import itemgetter
  
# initialising nested lists
ini_list = [[1, 2], [4, 3], [45, 65], [223, 2]]
  
# printing initial lists
print ("initial list", str(ini_list))
  
# code to split it into 2 lists
res1 = list(map(itemgetter(0), ini_list))
res2 = list(map(itemgetter(1), ini_list))
  
# printing result
print("final lists", str(res1), "\n", str(res2))

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Output:

initial list [[1, 2], [4, 3], [45, 65], [223, 2]]
final lists [1, 4, 45, 223] 
 [2, 3, 65, 2]

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