The simple list slicing has many applications and along with it many variations of list splitting also exists and can come to us to solve. One such problem can be to split K elements after every N values. Let’s discuss ways in which this particular problem can be solved.
Method #1 : Using loops
This is the Naive and brute force method to solve this particular problem with the help of loop, we can form a new list to check for K occurrences of elements after every N elements.
# Python3 code to demonstrate # Getting K elements after N values # using loops # initializing list test_list = [4, 5, 2, 7, 8, 4, 10, 9, 11, 13] # printing original list print("The original list : " + str(test_list)) # initializing N and K N = 2K = 3 # using loops # Getting K elements after N values res =[] while test_list: res += test_list[:K] test_list = test_list[K + N:] # print result print("The list after selective slicing : " + str(res)) |
The original list : [4, 5, 2, 7, 8, 4, 10, 9, 11, 13] The list after selective slicing : [4, 5, 2, 4, 10, 9]
Method #2 : Using list comprehension
This particular task can be performed using the shortened way of the above method using the list comprehension, we also use list slicing in this method to perform necessary slicing.
# Python3 code to demonstrate # Getting K elements after N values # using list comprehension # initializing list test_list = [4, 5, 2, 7, 8, 4, 10, 9, 11, 13] # printing original list print("The original list : " + str(test_list)) # initializing N and K N = 2K = 3 # using list comprehension # Getting K elements after N values res = [y for x in [test_list[i : i + K] for i in range(0, len(test_list), N + K)] for y in x] # print result print("The list after selective slicing : " + str(res)) |
The original list : [4, 5, 2, 7, 8, 4, 10, 9, 11, 13] The list after selective slicing : [4, 5, 2, 4, 10, 9]
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