Python | Sort Tuples in Increasing Order by any key

Given a tuple, sort the list of tuples in increasing order by any key in tuple.

**Examples:**

Input : tuple = [(2, 5), (1, 2), (4, 4), (2, 3)] m = 0 Output : [(1, 2), (2, 3), (2, 5), (4, 4)] Explanation: Sorted using the 0th index key. Input : [(23, 45, 20), (25, 44, 39), (89, 40, 23)] m = 2 Output : Sorted: [(23, 45, 20), (89, 40, 23), (25, 44, 39)] Explanation: Sorted using the 2nd index key

Given tuples, we need to sort them according to any given key. This can be done using sorted() function where we sort them using **key=last** and store last as the key index according to which we have to sort the given tuples.

*Below is the Python implementation of the above approach:*

`# Python code to sort a list of tuples ` `# according to given key.` ` ` `# get the last key.` `def` `last(n):` ` ` `return` `n[m] ` ` ` `# function to sort the tuple ` `def` `sort(tuples):` ` ` ` ` `# We pass used defined function last` ` ` `# as a parameter. ` ` ` `return` `sorted` `(tuples, key ` `=` `last)` ` ` `# driver code ` `a ` `=` `[(` `23` `, ` `45` `, ` `20` `), (` `25` `, ` `44` `, ` `39` `), (` `89` `, ` `40` `, ` `23` `)]` `m ` `=` `2` `print` `(` `"Sorted:"` `),` `print` `(sort(a))` |

Output:

Sorted: [(23, 45, 20), (89, 40, 23), (25, 44, 39)]

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