# Python | Sort Tuples in Increasing Order by any key

• Difficulty Level : Hard
• Last Updated : 18 Dec, 2017

Given a tuple, sort the list of tuples in increasing order by any key in tuple.

Examples:

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```Input : tuple = [(2, 5), (1, 2), (4, 4), (2, 3)]
m = 0
Output : [(1, 2), (2, 3), (2, 5), (4, 4)]
Explanation: Sorted using the 0th index key.

Input :  [(23, 45, 20), (25, 44, 39), (89, 40, 23)]
m = 2
Output : Sorted: [(23, 45, 20), (89, 40, 23), (25, 44, 39)]
Explanation: Sorted using the 2nd index key
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Given tuples, we need to sort them according to any given key. This can be done using sorted() function where we sort them using key=last and store last as the key index according to which we have to sort the given tuples.

Below is the Python implementation of the above approach:

 `# Python code to sort a list of tuples ``# according to given key.`` ` `# get the last key.``def` `last(n):``    ``return` `n[m]  ``  ` `# function to sort the tuple   ``def` `sort(tuples):`` ` `    ``# We pass used defined function last``    ``# as a parameter. ``    ``return` `sorted``(tuples, key ``=` `last)``  ` `# driver code  ``a ``=` `[(``23``, ``45``, ``20``), (``25``, ``44``, ``39``), (``89``, ``40``, ``23``)]``m ``=` `2``print``(``"Sorted:"``),``print``(sort(a))`

Output:

```Sorted: [(23, 45, 20), (89, 40, 23), (25, 44, 39)]
```
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