# Python | Sort tuple list by Nth element of tuple

• Last Updated : 11 May, 2020

Sometimes, while working with Python list, we can come across a problem in which we need to sort list according to any tuple element. These must be a generic way to perform the sort by particular tuple index. This has a good utility in web development domain. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using `sort() + lambda`
The combination of above functions can be used to perform this task. In this, we just pass a lambda function to `sort()` with appropriate tuple element index according to which sort has to be performed.

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 `# Python3 code to demonstrate working of``# Sort tuple list by Nth element of tuple``# using sort() + lambda`` ` `# initializing list``test_list ``=` `[(``4``, ``5``, ``1``), (``6``, ``1``, ``5``), (``7``, ``4``, ``2``), (``6``, ``2``, ``4``)]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# index according to which sort to perform``N ``=` `1`` ` `# Sort tuple list by Nth element of tuple``# using sort() + lambda``test_list.sort(key ``=` `lambda` `x: x[N])`` ` `# printing result ``print``(``"List after sorting tuple by Nth index sort : "` `+` `str``(test_list))`
Output :

```The original list is : [(4, 5, 1), (6, 1, 5), (7, 4, 2), (6, 2, 4)]
List after sorting tuple by Nth index sort : [(6, 1, 5), (6, 2, 4), (7, 4, 2), (4, 5, 1)]
```

Method #2 : Using `sort() + itemgetter()`
This is similar to the above method. The difference is just that we use `itemgetter()`, to perform this task that is done by lambda in above method.

 `# Python3 code to demonstrate working of``# Sort tuple list by Nth element of tuple``# using sort() + itemgetter()``from` `operator ``import` `itemgetter`` ` `# initializing list``test_list ``=` `[(``4``, ``5``, ``1``), (``6``, ``1``, ``5``), (``7``, ``4``, ``2``), (``6``, ``2``, ``4``)]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# index according to which sort to perform``N ``=` `1`` ` `# Sort tuple list by Nth element of tuple``# using sort() + itemgetter()``test_list.sort(key ``=` `itemgetter(N))`` ` `# printing result ``print``(``"List after sorting tuple by Nth index sort : "` `+` `str``(test_list))`
Output :
```The original list is : [(4, 5, 1), (6, 1, 5), (7, 4, 2), (6, 2, 4)]
List after sorting tuple by Nth index sort : [(6, 1, 5), (6, 2, 4), (7, 4, 2), (4, 5, 1)]
```

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