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Python – Sort Strings by maximum frequency character

  • Last Updated : 02 Dec, 2020

Given a string, the task is to write a Python program to perform sort by maximum occurring character.

Input : test_list = [“geekforgeeks”, “bettered”, “for”, “geeks”] 
Output : [‘for’, ‘geeks’, ‘bettered’, ‘geekforgeeks’] 
Explanation : 1 < 2 < 3 < 4, is ordering of maximum character occurrence frequency.

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Input : test_list = [“geekforgeeks”, “for”, “geeks”] 
Output : [‘for’, ‘geeks’, ‘geekforgeeks’] 
Explanation : 1 < 2 < 4, is ordering of maximum character occurrence frequency. 
 



Method #1 : Using sort() + Counter() + max()

In this, we perform inplace sorting using sort(), and Counter() is used to compute characters frequency, max() used to get maximum of computed frequencies.

Python3




# Python3 code to demonstrate working of 
# Sort Strings by maximum frequency character
# Using sort() + Counter() + max()
from collections import Counter
  
# getting maximum character frequency
def max_freq(arg_str):
    res = Counter(arg_str) 
    return arg_str.count(max(res, key = res.get))
  
# initializing list
test_list = ["geekforgeeks", "bettered", "for", "geeks"]
  
# printing original list
print("The original list is : " + str(test_list))
  
# performing sort 
test_list.sort(key = max_freq)
  
# printing result 
print("Sorted List : " + str(test_list))

Output:

The original list is : ['geekforgeeks', 'bettered', 'for', 'geeks']
Sorted List : ['for', 'geeks', 'bettered', 'geekforgeeks']

Method #2 : Using sorted() + lambda + Counter()

In this, we perform the task of performing sort using sorted(), and lambda function to get a single statement logical expression, avoiding external function call.

Python3




# Python3 code to demonstrate working of 
# Sort Strings by maximum frequency character
# Using sorted() + lambda + Counter()
from collections import Counter
  
# getting maximum character frequency
def max_freq(arg_str):
    res = Counter(arg_str) 
    return arg_str.count(max(arg_str, key = arg_str.get))
  
# initializing list
test_list = ["geekforgeeks", "bettered", "for", "geeks"]
  
# printing original list
print("The original list is : " + str(test_list))
  
# performing sort 
# lambda function to drive logic
res = sorted(test_list, 
             key = lambda arg_str : arg_str.count(
               max(Counter(arg_str), key = Counter(arg_str).get)))
  
# printing result 
print("Sorted List : " + str(res))

Output:

The original list is : ['geekforgeeks', 'bettered', 'for', 'geeks']
Sorted List : ['for', 'geeks', 'bettered', 'geekforgeeks']



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